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AP Physics 1 – Orbits & Kepler’s Laws: v = √(GM/r) and T² ∝ r³
From satellites to moons: Objects in circular orbits are essentially falling forever. In this final guide for Unit 3, we derive the orbital velocity equation, prove Kepler’s Third Law, and solve AP-style orbit problems.
1. Orbital Velocity: The Gravity-Centripetal Balance
A satellite stays in orbit because the Gravitational Force pulls it inward with exactly the strength needed to provide the Centripetal Force.
The Derivation You Must Know
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Solve for v:
- Note: Little mass
(the satellite) cancels out! Speed depends only on the planet mass
and radius
.
Gravity is stronger, so you must move FASTER to stay in orbit.
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Gravity is stronger, so you must move FASTER.
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2. Orbital Period: Kepler’s Third Law
How long does one full orbit take? By combining velocity with the circle circumference formula (
), we find a powerful relationship.
. Substituting
gives us
.
This means if you know the radius, you know the period. They are locked together.
3. Kepler’s Three Laws (Summary)
- 1st Law (The Law of Ellipses): All planets move in elliptical orbits, with the sun at one focus. (Note: In AP Physics 1, we usually approximate orbits as perfect circles to make the math easier).
-
2nd Law (The Law of Equal Areas): A line that connects a planet to the sun sweeps out equal areas in equal times.
Physics Reason: This is a direct consequence of the Conservation of Angular Momentum. As the radius
decreases, speed
must increase to keep angular momentum
constant.
-
3rd Law (The Law of Harmonics): The square of the period of any planet is proportional to the cube of the semimajor axis of its orbit (
).
4. AP Physics 1 Practice Problems
Problem 1: The Speed Ratio
Satellite B orbits at distance
from the center of a planet. Satellite A orbits at distance
. How does the speed of Satellite B compare to A?
Click to see answer
Answer: ![]()
Formula:
.
Since
increased by factor of 4,
changes by factor of
.
Problem 2: Kepler’s Calculation
A planet takes 8 years to orbit a star at a distance of 4 AU. How long would it take to orbit at a distance of 1 AU?
Click to see answer
Answer: 1 year
Use ratio: ![]()
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.
